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NCERT Solutions for Class 10 Maths Chapter 13 - Surface Areas and Volumes Exercise 13.1- The chapter deals with three-dimensional geometric shapes. Also, these shapes cover some areas and occupy space. On the other hand, volumes are the amount of space available in an object. Furthermore, these shapes are complete solids and in our day to day.


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NCERT solutions for class-10 maths Chapter-13 Surface Area and Volmunes is prepared by academic team of Physics Wallah. We have prepared solutions for all exercises of this chapter. Given below is step by step solutions of all questions given in NCERT textbook for chapter-13. You have learned the formula of the given chapter.


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A User-Friendly Guide for 10th Maths Exercise 13.1. One of the primary advantages of the NCERT solutions is its user-friendly nature. Concepts are broken down into smaller, digestible sections. Each problem is approached systematically, elucidating the underlying principles before diving into the solution.


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Answer: The diagram is given as Given, The Volume (V) of each cube is = 64 cm 3 This implies that a 3 = 64 cm 3 ∴ a = 4 cm Now, the side of the cube = a = 4 cm Also, the length and breadth of the resulting cuboid will be 4 cm each, while its height will be 8 cm. So, the surface area of the cuboid = 2 (lb+bh+lh) = 2 (8×4+4×4+4×8) cm 2


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Here you will find free Ex 13.1 Class 10 Maths NCERT Solutions Chapter 13 PDF to complete your homework on time. These Solutions are part of NCERT Solutions for Class 10 Maths in Hindi Medium. Here we have given NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes. Chapter 13. पृष्ठीय क्षेत्रफल एवं आयतन प्रश्नावली 13.1


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Solution: Ex 13.1 Class 10 Maths Question 2. A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the hemisphere is 14 cm and the total height of the vessel is 13 cm. Find the inner surface area of the vessel. Solution:


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Free PDF download of NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.1 (Ex 13.1) and all chapter exercises at one place prepared by an expert teacher as per NCERT (CBSE) books guidelines. Class 10 Maths Chapter 13 Surface Areas And Volumes Exercise 13.1 Questions with Solutions to help you to revise complete Syllabus and Score More marks.


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Chapter 1 Real Numbers Chapter 2 Polynomials Chapter 3 Pair of Linear Equations in Two Variables Chapter 4 Quadratic Equations Chapter 5 Arithmetic Progressions Chapter 6 Triangles Chapter 7 Coordinate Geometry Chapter 8 Introduction to Trigonometry Chapter 9 Applications of Trigonometry Chapter 10 Circle Chapter 11 Constructions


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Solution: Exercise 13.1 Class 10 NCERT Solutions Question 8. From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest cm². Solution:


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Solution: Note: PQ = √119 Ex 10.1 Class 10 Maths Question 4. Draw a circle and two lines parallel to a given line such that one is a tangent and the other, a secant to the circle. Solution:


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NCERT Solutions for Class 10 Maths Hindi and English Medium for 2019 Board Exams solved by expert teachers from latest edition books and as per NCERT (CBSE) guidelines.


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Solution: Ex 13.3 Class 10 Maths Question 2. Metallic spheres of radii 6 cm, 8 cm and 10 cm, respectively, are melted to form a single solid sphere. Find the radius of the resulting sphere. Solution: Download NCERT Solutions For Class 10 Maths Chapter 13 Surface Areas and Volumes PDF Ex 13.3 Class 10 Maths Question 3.


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Given, The Volume (V) of each cube is = 64 cm 3 This implies that a 3 = 64 cm 3 ∴ a = 4 cm Now, the side of the cube = a = 4 cm Also, the length and breadth of the resulting cuboid will be 4 cm each, while its height will be 8 cm. So, the surface area of the cuboid = 2 (lb+bh+lh) = 2 (8×4+4×4+4×8) cm 2 = 2 (32+16+32) cm 2 = (2×80) cm 2 = 160 cm 2